9. THE CALCULATION OF THE STEREO BASE |
Prerequisite:
Deviation = constant
bN - bF
= = constant
For simplifications, assume:
bF = bO
The triangle with the opposite angles
are similar, therefore:
|
|
||||||||||||
|
|
|
|
||||||||||
|
|
||||||||||||
|
|
||||||||||||
|
|
|
|
|
|||||||||
|
|
||||||||||||
|
|
|
|
|
|
||||||||
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
||||||||
|
|
||||||||||||
|
|
|
|
|
|
|
|||||||
|
|
||||||||||||
|
|
||||||||||||
|
|
|
|
|
|
|
|||||||
|
|
||||||||||||
|
|
||||||||||||
|
|
|
|
|
|
|
|
|
|
||||
|
|
Since the value of a', the image distance
in the camera, can hardly be measured, it is replaced with help of a well-known
optical formula.
The assumption: aN/a
= 1 distorts the result only ever so slightly. With a large amount of depth
of field ts, a can be significantly larger
when aN is big.
The value aN/f then is very large. With a small aN the value of a, the object distance = focal range, is not much larger, since then the depth of field ts, dependent on the aperture, is also not large.
The value of aN/f is then small too. Subtracting 1 or 0.8, for example, makes no difference.
According to the above equation, the stereo base bO is dependent upon the selected stereo window distance from which is derived, from the focal length f and the near-point distance aN. and usually f are constants so that only the near-point distance remains. The far-point distance is not of importance and must be considered in the choice of the aperture.
If one calculates the enlargement factor V from the known formulas for the focal length f, object- and image distance a, a' and substitutes them into the equation for the calculation of the base, this equation simplifies to bs = /V.
Since both the depth of field and the exposure
factor are dependent on the enlargement factor, all the relations can be
depicted on graph 4. This is of special interest to macro- and micro-stereo-photography,
where a lot of work involves the enlargement factor. Graph 5 shows the
base dependent on the enlargement factor with different focal lengths =
picture diagonals.
Previous
Chapter: Do-It-Yourself Directions |
Contents |
Next
Chapter: English / German Technical Keywords |
|
Back to the Services Page |